Optimal. Leaf size=110 \[ \frac {a^{3/2} (5 A b-7 a B) \tan ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a}}\right )}{2 b^{9/2}}-\frac {a^2 x (A b-a B)}{2 b^4 \left (a+b x^2\right )}-\frac {a x (2 A b-3 a B)}{b^4}+\frac {x^3 (A b-2 a B)}{3 b^3}+\frac {B x^5}{5 b^2} \]
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Rubi [A] time = 0.11, antiderivative size = 110, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.150, Rules used = {455, 1810, 205} \[ -\frac {a^2 x (A b-a B)}{2 b^4 \left (a+b x^2\right )}+\frac {a^{3/2} (5 A b-7 a B) \tan ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a}}\right )}{2 b^{9/2}}+\frac {x^3 (A b-2 a B)}{3 b^3}-\frac {a x (2 A b-3 a B)}{b^4}+\frac {B x^5}{5 b^2} \]
Antiderivative was successfully verified.
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Rule 205
Rule 455
Rule 1810
Rubi steps
\begin {align*} \int \frac {x^6 \left (A+B x^2\right )}{\left (a+b x^2\right )^2} \, dx &=-\frac {a^2 (A b-a B) x}{2 b^4 \left (a+b x^2\right )}-\frac {\int \frac {-a^2 (A b-a B)+2 a b (A b-a B) x^2-2 b^2 (A b-a B) x^4-2 b^3 B x^6}{a+b x^2} \, dx}{2 b^4}\\ &=-\frac {a^2 (A b-a B) x}{2 b^4 \left (a+b x^2\right )}-\frac {\int \left (2 a (2 A b-3 a B)-2 b (A b-2 a B) x^2-2 b^2 B x^4+\frac {-5 a^2 A b+7 a^3 B}{a+b x^2}\right ) \, dx}{2 b^4}\\ &=-\frac {a (2 A b-3 a B) x}{b^4}+\frac {(A b-2 a B) x^3}{3 b^3}+\frac {B x^5}{5 b^2}-\frac {a^2 (A b-a B) x}{2 b^4 \left (a+b x^2\right )}+\frac {\left (a^2 (5 A b-7 a B)\right ) \int \frac {1}{a+b x^2} \, dx}{2 b^4}\\ &=-\frac {a (2 A b-3 a B) x}{b^4}+\frac {(A b-2 a B) x^3}{3 b^3}+\frac {B x^5}{5 b^2}-\frac {a^2 (A b-a B) x}{2 b^4 \left (a+b x^2\right )}+\frac {a^{3/2} (5 A b-7 a B) \tan ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a}}\right )}{2 b^{9/2}}\\ \end {align*}
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Mathematica [A] time = 0.08, size = 111, normalized size = 1.01 \[ -\frac {a^{3/2} (7 a B-5 A b) \tan ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a}}\right )}{2 b^{9/2}}-\frac {x \left (a^2 A b-a^3 B\right )}{2 b^4 \left (a+b x^2\right )}+\frac {a x (3 a B-2 A b)}{b^4}+\frac {x^3 (A b-2 a B)}{3 b^3}+\frac {B x^5}{5 b^2} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.50, size = 298, normalized size = 2.71 \[ \left [\frac {12 \, B b^{3} x^{7} - 4 \, {\left (7 \, B a b^{2} - 5 \, A b^{3}\right )} x^{5} + 20 \, {\left (7 \, B a^{2} b - 5 \, A a b^{2}\right )} x^{3} - 15 \, {\left (7 \, B a^{3} - 5 \, A a^{2} b + {\left (7 \, B a^{2} b - 5 \, A a b^{2}\right )} x^{2}\right )} \sqrt {-\frac {a}{b}} \log \left (\frac {b x^{2} + 2 \, b x \sqrt {-\frac {a}{b}} - a}{b x^{2} + a}\right ) + 30 \, {\left (7 \, B a^{3} - 5 \, A a^{2} b\right )} x}{60 \, {\left (b^{5} x^{2} + a b^{4}\right )}}, \frac {6 \, B b^{3} x^{7} - 2 \, {\left (7 \, B a b^{2} - 5 \, A b^{3}\right )} x^{5} + 10 \, {\left (7 \, B a^{2} b - 5 \, A a b^{2}\right )} x^{3} - 15 \, {\left (7 \, B a^{3} - 5 \, A a^{2} b + {\left (7 \, B a^{2} b - 5 \, A a b^{2}\right )} x^{2}\right )} \sqrt {\frac {a}{b}} \arctan \left (\frac {b x \sqrt {\frac {a}{b}}}{a}\right ) + 15 \, {\left (7 \, B a^{3} - 5 \, A a^{2} b\right )} x}{30 \, {\left (b^{5} x^{2} + a b^{4}\right )}}\right ] \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.27, size = 115, normalized size = 1.05 \[ -\frac {{\left (7 \, B a^{3} - 5 \, A a^{2} b\right )} \arctan \left (\frac {b x}{\sqrt {a b}}\right )}{2 \, \sqrt {a b} b^{4}} + \frac {B a^{3} x - A a^{2} b x}{2 \, {\left (b x^{2} + a\right )} b^{4}} + \frac {3 \, B b^{8} x^{5} - 10 \, B a b^{7} x^{3} + 5 \, A b^{8} x^{3} + 45 \, B a^{2} b^{6} x - 30 \, A a b^{7} x}{15 \, b^{10}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.01, size = 132, normalized size = 1.20 \[ \frac {B \,x^{5}}{5 b^{2}}+\frac {A \,x^{3}}{3 b^{2}}-\frac {2 B a \,x^{3}}{3 b^{3}}-\frac {A \,a^{2} x}{2 \left (b \,x^{2}+a \right ) b^{3}}+\frac {5 A \,a^{2} \arctan \left (\frac {b x}{\sqrt {a b}}\right )}{2 \sqrt {a b}\, b^{3}}+\frac {B \,a^{3} x}{2 \left (b \,x^{2}+a \right ) b^{4}}-\frac {7 B \,a^{3} \arctan \left (\frac {b x}{\sqrt {a b}}\right )}{2 \sqrt {a b}\, b^{4}}-\frac {2 A a x}{b^{3}}+\frac {3 B \,a^{2} x}{b^{4}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 2.23, size = 112, normalized size = 1.02 \[ \frac {{\left (B a^{3} - A a^{2} b\right )} x}{2 \, {\left (b^{5} x^{2} + a b^{4}\right )}} - \frac {{\left (7 \, B a^{3} - 5 \, A a^{2} b\right )} \arctan \left (\frac {b x}{\sqrt {a b}}\right )}{2 \, \sqrt {a b} b^{4}} + \frac {3 \, B b^{2} x^{5} - 5 \, {\left (2 \, B a b - A b^{2}\right )} x^{3} + 15 \, {\left (3 \, B a^{2} - 2 \, A a b\right )} x}{15 \, b^{4}} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.05, size = 141, normalized size = 1.28 \[ x^3\,\left (\frac {A}{3\,b^2}-\frac {2\,B\,a}{3\,b^3}\right )-x\,\left (\frac {2\,a\,\left (\frac {A}{b^2}-\frac {2\,B\,a}{b^3}\right )}{b}+\frac {B\,a^2}{b^4}\right )+\frac {B\,x^5}{5\,b^2}+\frac {x\,\left (\frac {B\,a^3}{2}-\frac {A\,a^2\,b}{2}\right )}{b^5\,x^2+a\,b^4}-\frac {a^{3/2}\,\mathrm {atan}\left (\frac {a^{3/2}\,\sqrt {b}\,x\,\left (5\,A\,b-7\,B\,a\right )}{7\,B\,a^3-5\,A\,a^2\,b}\right )\,\left (5\,A\,b-7\,B\,a\right )}{2\,b^{9/2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [B] time = 0.72, size = 211, normalized size = 1.92 \[ \frac {B x^{5}}{5 b^{2}} + x^{3} \left (\frac {A}{3 b^{2}} - \frac {2 B a}{3 b^{3}}\right ) + x \left (- \frac {2 A a}{b^{3}} + \frac {3 B a^{2}}{b^{4}}\right ) + \frac {x \left (- A a^{2} b + B a^{3}\right )}{2 a b^{4} + 2 b^{5} x^{2}} + \frac {\sqrt {- \frac {a^{3}}{b^{9}}} \left (- 5 A b + 7 B a\right ) \log {\left (- \frac {b^{4} \sqrt {- \frac {a^{3}}{b^{9}}} \left (- 5 A b + 7 B a\right )}{- 5 A a b + 7 B a^{2}} + x \right )}}{4} - \frac {\sqrt {- \frac {a^{3}}{b^{9}}} \left (- 5 A b + 7 B a\right ) \log {\left (\frac {b^{4} \sqrt {- \frac {a^{3}}{b^{9}}} \left (- 5 A b + 7 B a\right )}{- 5 A a b + 7 B a^{2}} + x \right )}}{4} \]
Verification of antiderivative is not currently implemented for this CAS.
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